MaxProductOfThree
Maximize A[P] * A[Q] * A[R] for any triplet (P, Q, R).
Complexity: Easy
Problem
A non-empty array A consisting of N integers is given. The product of triplet (P, Q, R) equates to A[P] * A[Q] * A[R] (0 ≤ P < Q < R < N).
Your goal is to find the maximal product of any triplet.
Write a function:
def solution(A)
that, given a non-empty array A, returns the value of the maximal product of any triplet.
Write an efficient algorithm for the following assumptions:
N is an integer within the range [3..100,000];
each element of array A is an integer within the range [−1,000..1,000].
Example
For example, array A such that:
A[0] = -3
A[1] = 1
A[2] = 2
A[3] = -2
A[4] = 5
A[5] = 6
contains the following example triplets:
(0, 1, 2), product is −3 * 1 * 2 = −6
(1, 2, 4), product is 1 * 2 * 5 = 10
(2, 4, 5), product is 2 * 5 * 6 = 60
The function should return 60, as the product of triplet (2, 4, 5) is maximal.
Code
def solution(A): A.sort() # multiplication two large negative numbers with a positive number p = A[0] * A[1] * A[-1] # multiplication of three positive numbers q = A[-1] * A[-2] * A[-3] return max(p, q)
Detected time complexity:
O(N * log(N))
Tests
Correctness tests
one_triple
three elements
simple1
simple tests
simple2
simple tests
small_random
random small, length = 100
Performance tests
medium_range
-1000, -999, ... 1000, length = ~1,000
medium_random
random medium, length = ~10,000
large_random
random large, length = ~100,000
large_range
2000 * (-10..10) + [-1000, 500, -1]
extreme_large
(-2, .., -2, 1, .., 1) and (MAX_INT)..(MAX_INT), length = ~100,000
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