Saturday, January 13, 2024

Can you give the example of an odd integrand and prove that it is odd?

Example of an odd integrand and it's proof.

Certainly! Let's consider the function f ( x ) = x 3 f(x) = x^3 . We'll integrate this function over a symmetric interval, say [ a , a ] [-a, a] , and then show that the result is zero, proving that f ( x ) f(x) is an odd function.

The integral is given by:

a a x 3 d x \int_{-a}^{a} x^3 \,dx

To evaluate this integral, we'll use the properties of odd functions. An odd function f ( x ) f(x) satisfies f ( x ) = f ( x ) f(-x) = -f(x) . Let's evaluate f ( x ) f(-x) for f ( x ) = x 3 f(x) = x^3 :

f ( x ) = ( x ) 3 = x 3 f(-x) = (-x)^3 = -x^3

Now, compare f ( x ) f(-x) with f ( x ) -f(x) :

f ( x ) = x 3 -f(x) = -x^3

As we can see, f ( x ) = f ( x ) f(-x) = -f(x) . This property holds for all values of x x .

Now, let's calculate the integral:

a a x 3 d x = 1 4 x 4 a a \int_{-a}^{a} x^3 \,dx = \frac{1}{4}x^4 \Big|_{-a}^{a}

= 1 4 ( a 4 ( a ) 4 ) = \frac{1}{4}(a^4 - (-a)^4)

= 1 4 ( a 4 a 4 ) = \frac{1}{4}(a^4 - a^4)

= 1 4 ( 0 ) = \frac{1}{4}(0)

= 0 = 0

The result is zero, which means that the integral of the odd function f ( x ) = x 3 f(x) = x^3 over the symmetric interval [ a , a ] [-a, a] is zero. This demonstrates that f ( x ) = x 3 f(x) = x^3 is an odd function.

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