Question: I'm making 2 queries (or a single query) to the database. What I want to achieve: If one of them is null, I want to add the value 'nil'. Example: field1: nil, field2: 'value' If both are null, then I want it to respond with the 'not found' message. What's a good approach for this? Answer:First, we setup the local database.
Running a local instance
(base) ashish@ashishlaptop:~/Desktop$ mongosh Current Mongosh Log ID: 63498870b0f4b94029f7b626 Connecting to: mongodb://127.0.0.1:27017/?directConnection=true&serverSelectionTimeoutMS=2000&appName=mongosh+1.6.0 Using MongoDB: 6.0.2 Using Mongosh: 1.6.0 For mongosh info see: https://docs.mongodb.com/mongodb-shell/ To help improve our products, anonymous usage data is collected and sent to MongoDB periodically (https://www.mongodb.com/legal/privacy-policy). You can opt-out by running the disableTelemetry() command. ------ The server generated these startup warnings when booting 2022-10-14T21:33:50.958+05:30: Using the XFS filesystem is strongly recommended with the WiredTiger storage engine. See http://dochub.mongodb.org/core/prodnotes-filesystem 2022-10-14T21:33:52.643+05:30: Access control is not enabled for the database. Read and write access to data and configuration is unrestricted 2022-10-14T21:33:52.644+05:30: vm.max_map_count is too low ------ ------ Enable MongoDB's free cloud-based monitoring service, which will then receive and display metrics about your deployment (disk utilization, CPU, operation statistics, etc). The monitoring data will be available on a MongoDB website with a unique URL accessible to you and anyone you share the URL with. MongoDB may use this information to make product improvements and to suggest MongoDB products and deployment options to you. To enable free monitoring, run the following command: db.enableFreeMonitoring() To permanently disable this reminder, run the following command: db.disableFreeMonitoring() ------ test> test> db test test> show dbs admin 40.00 KiB config 12.00 KiB local 72.00 KiB test> test> test> db.createCollection("ccn1") { ok: 1 } test> db.ccn1.insertOne({"name":"Ashish Jain","address":"Delhi"}) { acknowledged: true, insertedId: ObjectId("634989627d163a41b75e1e13") } test> Next Command db.ccn1.insertMany([ {"name":"","address":"India"}, {"name":"","address":""}, {"name":"Ash","address":""} ]) test> db.ccn1.insertMany([ ... {"name":"","address":"India"}, ... {"name":"","address":""}, ... {"name":"Ash","address":""} ... ]) { acknowledged: true, insertedIds: { '0': ObjectId("634989cc7d163a41b75e1e14"), '1': ObjectId("634989cc7d163a41b75e1e15"), '2': ObjectId("634989cc7d163a41b75e1e16") } } test>Our Database Looks Like This
[ { _id: new ObjectId("634989627d163a41b75e1e13"), name: 'Ashish Jain', address: 'Delhi' }, { _id: new ObjectId("634989cc7d163a41b75e1e14"), name: '', address: 'India' }, { _id: new ObjectId("634989cc7d163a41b75e1e15"), name: '', address: '' }, { _id: new ObjectId("634989cc7d163a41b75e1e16"), name: 'Ash', address: '' } ]This is our Node.js code in file "script.js"
var MongoClient = require('mongodb').MongoClient; var url = "mongodb://localhost:27017/"; MongoClient.connect(url, function(err, db) { if (err) throw err; var dbo = db.db("test"); var all_docs = dbo.collection("ccn1").find({}).toArray(function(err, result) { if (err) throw err; for (i in result){ if(result[i]['name'] && result[i]['address']) { console.log("name: " + result[i]['name']) console.log("address: " + result[i]['address']) } else if (result[i]['name'] && !result[i]['address']){ console.log("name: " + result[i]['name']) console.log("address: nil") } else if (!result[i]['name'] && result[i]['address']){ console.log("name: nil") console.log("address: " + result[i]['address']) } else { console.log("Not Found") } console.log() } db.close(); }); });This is our output
(base) ashish@ashishlaptop:~/Desktop/software/node$ node script.js name: Ashish Jain address: Delhi name: nil address: India Not Found name: Ash address: nil
Friday, October 14, 2022
Node.js and MongoDB Solved Interview Problem (Oct 2022)
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